3.5.56 \(\int \frac {\sqrt {a+b x^3} (c+d x+e x^2+f x^3+g x^4)}{x^8} \, dx\) [456]

3.5.56.1 Optimal result
3.5.56.2 Mathematica [C] (verified)
3.5.56.3 Rubi [A] (verified)
3.5.56.4 Maple [A] (verified)
3.5.56.5 Fricas [C] (verification not implemented)
3.5.56.6 Sympy [A] (verification not implemented)
3.5.56.7 Maxima [F]
3.5.56.8 Giac [F]
3.5.56.9 Mupad [F(-1)]

3.5.56.1 Optimal result

Integrand size = 35, antiderivative size = 711 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=-\frac {1}{420} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right ) \sqrt {a+b x^3}-\frac {3 b c \sqrt {a+b x^3}}{56 a x^4}-\frac {b d \sqrt {a+b x^3}}{12 a x^3}-\frac {3 b e \sqrt {a+b x^3}}{20 a x^2}+\frac {3 b (5 b c-14 a f) \sqrt {a+b x^3}}{112 a^2 x}-\frac {3 b^{4/3} (5 b c-14 a f) \sqrt {a+b x^3}}{112 a^2 \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {b (b d-4 a g) \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )}{12 a^{3/2}}+\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} b^{4/3} (5 b c-14 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{224 a^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {3^{3/4} \sqrt {2+\sqrt {3}} b^{4/3} \left (28 a^{2/3} \sqrt [3]{b} e-5 \left (1-\sqrt {3}\right ) (5 b c-14 a f)\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right ),-7-4 \sqrt {3}\right )}{560 a^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]

output
1/12*b*(-4*a*g+b*d)*arctanh((b*x^3+a)^(1/2)/a^(1/2))/a^(3/2)-1/420*(60*c/x 
^7+70*d/x^6+84*e/x^5+105*f/x^4+140*g/x^3)*(b*x^3+a)^(1/2)-3/56*b*c*(b*x^3+ 
a)^(1/2)/a/x^4-1/12*b*d*(b*x^3+a)^(1/2)/a/x^3-3/20*b*e*(b*x^3+a)^(1/2)/a/x 
^2+3/112*b*(-14*a*f+5*b*c)*(b*x^3+a)^(1/2)/a^2/x-3/112*b^(4/3)*(-14*a*f+5* 
b*c)*(b*x^3+a)^(1/2)/a^2/(b^(1/3)*x+a^(1/3)*(1+3^(1/2)))+3/224*3^(1/4)*b^( 
4/3)*(-14*a*f+5*b*c)*(a^(1/3)+b^(1/3)*x)*EllipticE((b^(1/3)*x+a^(1/3)*(1-3 
^(1/2)))/(b^(1/3)*x+a^(1/3)*(1+3^(1/2))),I*3^(1/2)+2*I)*(1/2*6^(1/2)-1/2*2 
^(1/2))*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(b^(1/3)*x+a^(1/3)*(1+3^( 
1/2)))^2)^(1/2)/a^(5/3)/(b*x^3+a)^(1/2)/(a^(1/3)*(a^(1/3)+b^(1/3)*x)/(b^(1 
/3)*x+a^(1/3)*(1+3^(1/2)))^2)^(1/2)-1/560*3^(3/4)*b^(4/3)*(a^(1/3)+b^(1/3) 
*x)*EllipticF((b^(1/3)*x+a^(1/3)*(1-3^(1/2)))/(b^(1/3)*x+a^(1/3)*(1+3^(1/2 
))),I*3^(1/2)+2*I)*(28*a^(2/3)*b^(1/3)*e-5*(-14*a*f+5*b*c)*(1-3^(1/2)))*(1 
/2*6^(1/2)+1/2*2^(1/2))*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(b^(1/3)* 
x+a^(1/3)*(1+3^(1/2)))^2)^(1/2)/a^(5/3)/(b*x^3+a)^(1/2)/(a^(1/3)*(a^(1/3)+ 
b^(1/3)*x)/(b^(1/3)*x+a^(1/3)*(1+3^(1/2)))^2)^(1/2)
 
3.5.56.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.49 (sec) , antiderivative size = 213, normalized size of antiderivative = 0.30 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=-\frac {\sqrt {a+b x^3} \left (180 a^3 c \operatorname {Hypergeometric2F1}\left (-\frac {7}{3},-\frac {1}{2},-\frac {4}{3},-\frac {b x^3}{a}\right )+7 x^2 \left (36 a^3 e \operatorname {Hypergeometric2F1}\left (-\frac {5}{3},-\frac {1}{2},-\frac {2}{3},-\frac {b x^3}{a}\right )+5 x \left (12 a^2 g x \left (a \sqrt {1+\frac {b x^3}{a}}+b x^3 \text {arctanh}\left (\sqrt {1+\frac {b x^3}{a}}\right )\right )+9 a^3 f \operatorname {Hypergeometric2F1}\left (-\frac {4}{3},-\frac {1}{2},-\frac {1}{3},-\frac {b x^3}{a}\right )+8 b^2 d x^4 \left (a+b x^3\right ) \sqrt {1+\frac {b x^3}{a}} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},3,\frac {5}{2},1+\frac {b x^3}{a}\right )\right )\right )\right )}{1260 a^3 x^7 \sqrt {1+\frac {b x^3}{a}}} \]

input
Integrate[(Sqrt[a + b*x^3]*(c + d*x + e*x^2 + f*x^3 + g*x^4))/x^8,x]
 
output
-1/1260*(Sqrt[a + b*x^3]*(180*a^3*c*Hypergeometric2F1[-7/3, -1/2, -4/3, -( 
(b*x^3)/a)] + 7*x^2*(36*a^3*e*Hypergeometric2F1[-5/3, -1/2, -2/3, -((b*x^3 
)/a)] + 5*x*(12*a^2*g*x*(a*Sqrt[1 + (b*x^3)/a] + b*x^3*ArcTanh[Sqrt[1 + (b 
*x^3)/a]]) + 9*a^3*f*Hypergeometric2F1[-4/3, -1/2, -1/3, -((b*x^3)/a)] + 8 
*b^2*d*x^4*(a + b*x^3)*Sqrt[1 + (b*x^3)/a]*Hypergeometric2F1[3/2, 3, 5/2, 
1 + (b*x^3)/a]))))/(a^3*x^7*Sqrt[1 + (b*x^3)/a])
 
3.5.56.3 Rubi [A] (verified)

Time = 1.54 (sec) , antiderivative size = 719, normalized size of antiderivative = 1.01, number of steps used = 18, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.486, Rules used = {2364, 27, 2374, 27, 2374, 27, 2374, 27, 2374, 25, 2371, 798, 73, 221, 2417, 759, 2416}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx\)

\(\Big \downarrow \) 2364

\(\displaystyle -\frac {3}{2} b \int -\frac {140 g x^4+105 f x^3+84 e x^2+70 d x+60 c}{420 x^5 \sqrt {b x^3+a}}dx-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{280} b \int \frac {140 g x^4+105 f x^3+84 e x^2+70 d x+60 c}{x^5 \sqrt {b x^3+a}}dx-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2374

\(\displaystyle \frac {1}{280} b \left (-\frac {\int -\frac {4 \left (280 a g x^3-15 (5 b c-14 a f) x^2+168 a e x+140 a d\right )}{x^4 \sqrt {b x^3+a}}dx}{8 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{280} b \left (\frac {\int \frac {280 a g x^3-15 (5 b c-14 a f) x^2+168 a e x+140 a d}{x^4 \sqrt {b x^3+a}}dx}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2374

\(\displaystyle \frac {1}{280} b \left (\frac {-\frac {\int -\frac {6 \left (168 e a^2-70 (b d-4 a g) x^2 a-15 (5 b c-14 a f) x a\right )}{x^3 \sqrt {b x^3+a}}dx}{6 a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {\int \frac {168 e a^2-70 (b d-4 a g) x^2 a-15 (5 b c-14 a f) x a}{x^3 \sqrt {b x^3+a}}dx}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2374

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\int \frac {4 \left (42 b e x^2 a^2+15 (5 b c-14 a f) a^2+70 (b d-4 a g) x a^2\right )}{x^2 \sqrt {b x^3+a}}dx}{4 a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\int \frac {42 b e x^2 a^2+15 (5 b c-14 a f) a^2+70 (b d-4 a g) x a^2}{x^2 \sqrt {b x^3+a}}dx}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2374

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {-\frac {\int -\frac {140 (b d-4 a g) a^3+84 b e x a^3+15 b (5 b c-14 a f) x^2 a^2}{x \sqrt {b x^3+a}}dx}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {\int \frac {140 (b d-4 a g) a^3+84 b e x a^3+15 b (5 b c-14 a f) x^2 a^2}{x \sqrt {b x^3+a}}dx}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2371

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {140 a^3 (b d-4 a g) \int \frac {1}{x \sqrt {b x^3+a}}dx+\int \frac {84 b e a^3+15 b (5 b c-14 a f) x a^2}{\sqrt {b x^3+a}}dx}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 798

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {\frac {140}{3} a^3 (b d-4 a g) \int \frac {1}{x^3 \sqrt {b x^3+a}}dx^3+\int \frac {84 b e a^3+15 b (5 b c-14 a f) x a^2}{\sqrt {b x^3+a}}dx}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {\frac {280 a^3 (b d-4 a g) \int \frac {1}{\frac {x^6}{b}-\frac {a}{b}}d\sqrt {b x^3+a}}{3 b}+\int \frac {84 b e a^3+15 b (5 b c-14 a f) x a^2}{\sqrt {b x^3+a}}dx}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {\int \frac {84 b e a^3+15 b (5 b c-14 a f) x a^2}{\sqrt {b x^3+a}}dx-\frac {280}{3} a^{5/2} \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) (b d-4 a g)}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2417

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {3 a^{7/3} b^{2/3} \left (28 a^{2/3} \sqrt [3]{b} e-5 \left (1-\sqrt {3}\right ) (5 b c-14 a f)\right ) \int \frac {1}{\sqrt {b x^3+a}}dx+15 a^2 b^{2/3} (5 b c-14 a f) \int \frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt {b x^3+a}}dx-\frac {280}{3} a^{5/2} \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) (b d-4 a g)}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 759

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {15 a^2 b^{2/3} (5 b c-14 a f) \int \frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt {b x^3+a}}dx+\frac {2\ 3^{3/4} \sqrt {2+\sqrt {3}} a^{7/3} \sqrt [3]{b} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right ) \left (28 a^{2/3} \sqrt [3]{b} e-5 \left (1-\sqrt {3}\right ) (5 b c-14 a f)\right )}{\sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {280}{3} a^{5/2} \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) (b d-4 a g)}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

\(\Big \downarrow \) 2416

\(\displaystyle \frac {1}{280} b \left (\frac {\frac {-\frac {\frac {\frac {2\ 3^{3/4} \sqrt {2+\sqrt {3}} a^{7/3} \sqrt [3]{b} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right ) \left (28 a^{2/3} \sqrt [3]{b} e-5 \left (1-\sqrt {3}\right ) (5 b c-14 a f)\right )}{\sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {280}{3} a^{5/2} \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) (b d-4 a g)+15 a^2 b^{2/3} (5 b c-14 a f) \left (\frac {2 \sqrt {a+b x^3}}{\sqrt [3]{b} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {\sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{\sqrt [3]{b} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}\right )}{2 a}-\frac {15 a \sqrt {a+b x^3} (5 b c-14 a f)}{x}}{a}-\frac {84 a e \sqrt {a+b x^3}}{x^2}}{a}-\frac {140 d \sqrt {a+b x^3}}{3 x^3}}{2 a}-\frac {15 c \sqrt {a+b x^3}}{a x^4}\right )-\frac {1}{420} \sqrt {a+b x^3} \left (\frac {60 c}{x^7}+\frac {70 d}{x^6}+\frac {84 e}{x^5}+\frac {105 f}{x^4}+\frac {140 g}{x^3}\right )\)

input
Int[(Sqrt[a + b*x^3]*(c + d*x + e*x^2 + f*x^3 + g*x^4))/x^8,x]
 
output
-1/420*(((60*c)/x^7 + (70*d)/x^6 + (84*e)/x^5 + (105*f)/x^4 + (140*g)/x^3) 
*Sqrt[a + b*x^3]) + (b*((-15*c*Sqrt[a + b*x^3])/(a*x^4) + ((-140*d*Sqrt[a 
+ b*x^3])/(3*x^3) + ((-84*a*e*Sqrt[a + b*x^3])/x^2 - ((-15*a*(5*b*c - 14*a 
*f)*Sqrt[a + b*x^3])/x + ((-280*a^(5/2)*(b*d - 4*a*g)*ArcTanh[Sqrt[a + b*x 
^3]/Sqrt[a]])/3 + 15*a^2*b^(2/3)*(5*b*c - 14*a*f)*((2*Sqrt[a + b*x^3])/(b^ 
(1/3)*((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x)) - (3^(1/4)*Sqrt[2 - Sqrt[3]]*a^ 
(1/3)*(a^(1/3) + b^(1/3)*x)*Sqrt[(a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^ 
2)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x)^2]*EllipticE[ArcSin[((1 - Sqrt[3])* 
a^(1/3) + b^(1/3)*x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x)], -7 - 4*Sqrt[3]] 
)/(b^(1/3)*Sqrt[(a^(1/3)*(a^(1/3) + b^(1/3)*x))/((1 + Sqrt[3])*a^(1/3) + b 
^(1/3)*x)^2]*Sqrt[a + b*x^3])) + (2*3^(3/4)*Sqrt[2 + Sqrt[3]]*a^(7/3)*b^(1 
/3)*(28*a^(2/3)*b^(1/3)*e - 5*(1 - Sqrt[3])*(5*b*c - 14*a*f))*(a^(1/3) + b 
^(1/3)*x)*Sqrt[(a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^2)/((1 + Sqrt[3])* 
a^(1/3) + b^(1/3)*x)^2]*EllipticF[ArcSin[((1 - Sqrt[3])*a^(1/3) + b^(1/3)* 
x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x)], -7 - 4*Sqrt[3]])/(Sqrt[(a^(1/3)*( 
a^(1/3) + b^(1/3)*x))/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x)^2]*Sqrt[a + b*x^ 
3]))/(2*a))/a)/a)/(2*a)))/280
 

3.5.56.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 759
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 + Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s 
*x + r^2*x^2)/((1 + Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[s* 
((s + r*x)/((1 + Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 - Sqrt[3])*s 
+ r*x)/((1 + Sqrt[3])*s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] & 
& PosQ[a]
 

rule 798
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/n   Subst 
[Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, 
b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
 

rule 2364
Int[(Pq_)*(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Module[{u 
 = IntHide[x^m*Pq, x]}, Simp[u*(a + b*x^n)^p, x] - Simp[b*n*p   Int[x^(m + 
n)*(a + b*x^n)^(p - 1)*ExpandToSum[u/x^(m + 1), x], x], x]] /; FreeQ[{a, b} 
, x] && PolyQ[Pq, x] && IGtQ[n, 0] && GtQ[p, 0] && LtQ[m + Expon[Pq, x] + 1 
, 0]
 

rule 2371
Int[(Pq_)/((x_)*Sqrt[(a_) + (b_.)*(x_)^(n_)]), x_Symbol] :> Simp[Coeff[Pq, 
x, 0]   Int[1/(x*Sqrt[a + b*x^n]), x], x] + Int[ExpandToSum[(Pq - Coeff[Pq, 
 x, 0])/x, x]/Sqrt[a + b*x^n], x] /; FreeQ[{a, b}, x] && PolyQ[Pq, x] && IG 
tQ[n, 0] && NeQ[Coeff[Pq, x, 0], 0]
 

rule 2374
Int[(Pq_)*((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Wit 
h[{Pq0 = Coeff[Pq, x, 0]}, Simp[Pq0*(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*c 
*(m + 1))), x] + Simp[1/(2*a*c*(m + 1))   Int[(c*x)^(m + 1)*ExpandToSum[2*a 
*(m + 1)*((Pq - Pq0)/x) - 2*b*Pq0*(m + n*(p + 1) + 1)*x^(n - 1), x]*(a + b* 
x^n)^p, x], x] /; NeQ[Pq0, 0]] /; FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] && 
 IGtQ[n, 0] && LtQ[m, -1] && LeQ[n - 1, Expon[Pq, x]]
 

rule 2416
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N 
umer[Simplify[(1 - Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 - Sqrt[3])*(d/c) 
]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 + Sqrt[3])*s + r*x))), x] - S 
imp[3^(1/4)*Sqrt[2 - Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( 
(1 + Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[s*((s + r*x)/((1 + Sqrt 
[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3]) 
*s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && PosQ[a] && Eq 
Q[b*c^3 - 2*(5 - 3*Sqrt[3])*a*d^3, 0]
 

rule 2417
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N 
umer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(c*r - (1 - Sqrt[3])*d*s)/r 
  Int[1/Sqrt[a + b*x^3], x], x] + Simp[d/r   Int[((1 - Sqrt[3])*s + r*x)/Sq 
rt[a + b*x^3], x], x]] /; FreeQ[{a, b, c, d}, x] && PosQ[a] && NeQ[b*c^3 - 
2*(5 - 3*Sqrt[3])*a*d^3, 0]
 
3.5.56.4 Maple [A] (verified)

Time = 1.82 (sec) , antiderivative size = 901, normalized size of antiderivative = 1.27

method result size
elliptic \(\text {Expression too large to display}\) \(901\)
risch \(\text {Expression too large to display}\) \(1283\)
default \(\text {Expression too large to display}\) \(1376\)

input
int((g*x^4+f*x^3+e*x^2+d*x+c)*(b*x^3+a)^(1/2)/x^8,x,method=_RETURNVERBOSE)
 
output
-1/7*c*(b*x^3+a)^(1/2)/x^7-1/6*d*(b*x^3+a)^(1/2)/x^6-1/5*e*(b*x^3+a)^(1/2) 
/x^5-1/56*(14*a*f+3*b*c)/a*(b*x^3+a)^(1/2)/x^4-1/12/a*(4*a*g+b*d)*(b*x^3+a 
)^(1/2)/x^3-3/20*b*e*(b*x^3+a)^(1/2)/a/x^2-3/112*(14*a*f-5*b*c)*b/a^2*(b*x 
^3+a)^(1/2)/x+1/20*I/a*b*e*3^(1/2)*(-a*b^2)^(1/3)*(I*(x+1/2/b*(-a*b^2)^(1/ 
3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b/(-a*b^2)^(1/3))^(1/2)*((x-1/b 
*(-a*b^2)^(1/3))/(-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3)))^( 
1/2)*(-I*(x+1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b 
/(-a*b^2)^(1/3))^(1/2)/(b*x^3+a)^(1/2)*EllipticF(1/3*3^(1/2)*(I*(x+1/2/b*( 
-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b/(-a*b^2)^(1/3))^(1 
/2),(I*3^(1/2)/b*(-a*b^2)^(1/3)/(-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a 
*b^2)^(1/3)))^(1/2))-1/112*I*(14*a*f-5*b*c)*b/a^2*3^(1/2)*(-a*b^2)^(1/3)*( 
I*(x+1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b/(-a*b^ 
2)^(1/3))^(1/2)*((x-1/b*(-a*b^2)^(1/3))/(-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/ 
2)/b*(-a*b^2)^(1/3)))^(1/2)*(-I*(x+1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(- 
a*b^2)^(1/3))*3^(1/2)*b/(-a*b^2)^(1/3))^(1/2)/(b*x^3+a)^(1/2)*((-3/2/b*(-a 
*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*EllipticE(1/3*3^(1/2)*(I*(x+1/ 
2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b/(-a*b^2)^(1/3 
))^(1/2),(I*3^(1/2)/b*(-a*b^2)^(1/3)/(-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/ 
b*(-a*b^2)^(1/3)))^(1/2))+1/b*(-a*b^2)^(1/3)*EllipticF(1/3*3^(1/2)*(I*(x+1 
/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*3^(1/2)*b/(-a*b^2)^...
 
3.5.56.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.15 (sec) , antiderivative size = 439, normalized size of antiderivative = 0.62 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=\left [-\frac {252 \, a b^{\frac {3}{2}} e x^{7} {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right ) + 35 \, {\left (b^{2} d - 4 \, a b g\right )} \sqrt {a} x^{7} \log \left (\frac {b^{2} x^{6} + 8 \, a b x^{3} - 4 \, {\left (b x^{3} + 2 \, a\right )} \sqrt {b x^{3} + a} \sqrt {a} + 8 \, a^{2}}{x^{6}}\right ) - 45 \, {\left (5 \, b^{2} c - 14 \, a b f\right )} \sqrt {b} x^{7} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right )\right ) + {\left (252 \, a b e x^{5} - 45 \, {\left (5 \, b^{2} c - 14 \, a b f\right )} x^{6} + 336 \, a^{2} e x^{2} + 140 \, {\left (a b d + 4 \, a^{2} g\right )} x^{4} + 280 \, a^{2} d x + 30 \, {\left (3 \, a b c + 14 \, a^{2} f\right )} x^{3} + 240 \, a^{2} c\right )} \sqrt {b x^{3} + a}}{1680 \, a^{2} x^{7}}, -\frac {252 \, a b^{\frac {3}{2}} e x^{7} {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right ) + 70 \, {\left (b^{2} d - 4 \, a b g\right )} \sqrt {-a} x^{7} \arctan \left (\frac {{\left (b x^{3} + 2 \, a\right )} \sqrt {b x^{3} + a} \sqrt {-a}}{2 \, {\left (a b x^{3} + a^{2}\right )}}\right ) - 45 \, {\left (5 \, b^{2} c - 14 \, a b f\right )} \sqrt {b} x^{7} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right )\right ) + {\left (252 \, a b e x^{5} - 45 \, {\left (5 \, b^{2} c - 14 \, a b f\right )} x^{6} + 336 \, a^{2} e x^{2} + 140 \, {\left (a b d + 4 \, a^{2} g\right )} x^{4} + 280 \, a^{2} d x + 30 \, {\left (3 \, a b c + 14 \, a^{2} f\right )} x^{3} + 240 \, a^{2} c\right )} \sqrt {b x^{3} + a}}{1680 \, a^{2} x^{7}}\right ] \]

input
integrate((g*x^4+f*x^3+e*x^2+d*x+c)*(b*x^3+a)^(1/2)/x^8,x, algorithm="fric 
as")
 
output
[-1/1680*(252*a*b^(3/2)*e*x^7*weierstrassPInverse(0, -4*a/b, x) + 35*(b^2* 
d - 4*a*b*g)*sqrt(a)*x^7*log((b^2*x^6 + 8*a*b*x^3 - 4*(b*x^3 + 2*a)*sqrt(b 
*x^3 + a)*sqrt(a) + 8*a^2)/x^6) - 45*(5*b^2*c - 14*a*b*f)*sqrt(b)*x^7*weie 
rstrassZeta(0, -4*a/b, weierstrassPInverse(0, -4*a/b, x)) + (252*a*b*e*x^5 
 - 45*(5*b^2*c - 14*a*b*f)*x^6 + 336*a^2*e*x^2 + 140*(a*b*d + 4*a^2*g)*x^4 
 + 280*a^2*d*x + 30*(3*a*b*c + 14*a^2*f)*x^3 + 240*a^2*c)*sqrt(b*x^3 + a)) 
/(a^2*x^7), -1/1680*(252*a*b^(3/2)*e*x^7*weierstrassPInverse(0, -4*a/b, x) 
 + 70*(b^2*d - 4*a*b*g)*sqrt(-a)*x^7*arctan(1/2*(b*x^3 + 2*a)*sqrt(b*x^3 + 
 a)*sqrt(-a)/(a*b*x^3 + a^2)) - 45*(5*b^2*c - 14*a*b*f)*sqrt(b)*x^7*weiers 
trassZeta(0, -4*a/b, weierstrassPInverse(0, -4*a/b, x)) + (252*a*b*e*x^5 - 
 45*(5*b^2*c - 14*a*b*f)*x^6 + 336*a^2*e*x^2 + 140*(a*b*d + 4*a^2*g)*x^4 + 
 280*a^2*d*x + 30*(3*a*b*c + 14*a^2*f)*x^3 + 240*a^2*c)*sqrt(b*x^3 + a))/( 
a^2*x^7)]
 
3.5.56.6 Sympy [A] (verification not implemented)

Time = 4.84 (sec) , antiderivative size = 308, normalized size of antiderivative = 0.43 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=\frac {\sqrt {a} c \Gamma \left (- \frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {7}{3}, - \frac {1}{2} \\ - \frac {4}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{7} \Gamma \left (- \frac {4}{3}\right )} + \frac {\sqrt {a} e \Gamma \left (- \frac {5}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{3}, - \frac {1}{2} \\ - \frac {2}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{5} \Gamma \left (- \frac {2}{3}\right )} + \frac {\sqrt {a} f \Gamma \left (- \frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {4}{3}, - \frac {1}{2} \\ - \frac {1}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{4} \Gamma \left (- \frac {1}{3}\right )} - \frac {a d}{6 \sqrt {b} x^{\frac {15}{2}} \sqrt {\frac {a}{b x^{3}} + 1}} - \frac {\sqrt {b} d}{4 x^{\frac {9}{2}} \sqrt {\frac {a}{b x^{3}} + 1}} - \frac {\sqrt {b} g \sqrt {\frac {a}{b x^{3}} + 1}}{3 x^{\frac {3}{2}}} - \frac {b^{\frac {3}{2}} d}{12 a x^{\frac {3}{2}} \sqrt {\frac {a}{b x^{3}} + 1}} - \frac {b g \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x^{\frac {3}{2}}} \right )}}{3 \sqrt {a}} + \frac {b^{2} d \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x^{\frac {3}{2}}} \right )}}{12 a^{\frac {3}{2}}} \]

input
integrate((g*x**4+f*x**3+e*x**2+d*x+c)*(b*x**3+a)**(1/2)/x**8,x)
 
output
sqrt(a)*c*gamma(-7/3)*hyper((-7/3, -1/2), (-4/3,), b*x**3*exp_polar(I*pi)/ 
a)/(3*x**7*gamma(-4/3)) + sqrt(a)*e*gamma(-5/3)*hyper((-5/3, -1/2), (-2/3, 
), b*x**3*exp_polar(I*pi)/a)/(3*x**5*gamma(-2/3)) + sqrt(a)*f*gamma(-4/3)* 
hyper((-4/3, -1/2), (-1/3,), b*x**3*exp_polar(I*pi)/a)/(3*x**4*gamma(-1/3) 
) - a*d/(6*sqrt(b)*x**(15/2)*sqrt(a/(b*x**3) + 1)) - sqrt(b)*d/(4*x**(9/2) 
*sqrt(a/(b*x**3) + 1)) - sqrt(b)*g*sqrt(a/(b*x**3) + 1)/(3*x**(3/2)) - b** 
(3/2)*d/(12*a*x**(3/2)*sqrt(a/(b*x**3) + 1)) - b*g*asinh(sqrt(a)/(sqrt(b)* 
x**(3/2)))/(3*sqrt(a)) + b**2*d*asinh(sqrt(a)/(sqrt(b)*x**(3/2)))/(12*a**( 
3/2))
 
3.5.56.7 Maxima [F]

\[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=\int { \frac {{\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a}}{x^{8}} \,d x } \]

input
integrate((g*x^4+f*x^3+e*x^2+d*x+c)*(b*x^3+a)^(1/2)/x^8,x, algorithm="maxi 
ma")
 
output
integrate((g*x^4 + f*x^3 + e*x^2 + d*x + c)*sqrt(b*x^3 + a)/x^8, x)
 
3.5.56.8 Giac [F]

\[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=\int { \frac {{\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a}}{x^{8}} \,d x } \]

input
integrate((g*x^4+f*x^3+e*x^2+d*x+c)*(b*x^3+a)^(1/2)/x^8,x, algorithm="giac 
")
 
output
integrate((g*x^4 + f*x^3 + e*x^2 + d*x + c)*sqrt(b*x^3 + a)/x^8, x)
 
3.5.56.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^8} \, dx=\int \frac {\sqrt {b\,x^3+a}\,\left (g\,x^4+f\,x^3+e\,x^2+d\,x+c\right )}{x^8} \,d x \]

input
int(((a + b*x^3)^(1/2)*(c + d*x + e*x^2 + f*x^3 + g*x^4))/x^8,x)
 
output
int(((a + b*x^3)^(1/2)*(c + d*x + e*x^2 + f*x^3 + g*x^4))/x^8, x)